Example:
Design a suitable conductor to carry a current of 100A.
Solution:
Let us assume the material is copper
copper has a current carrying capacity of 6A/sq.mm.
We know that the property of current, it only flows through the surface of the conductor.
so 1sq.mm copper has a current carrying capacity of 6A
there fore, 1A current must be carried by 0.1667sq.mm copper conductor
there fore, 100A will carried by a conductor of 16.667sq.mm area.
Design the conductor for 20sq.mm
Let us assume one conductor is cylindrical shape and another one is square prism.
Surface area of cylinder = pi x d x L + pi x (d/2)2
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